Hello all!
I’m back, 2 weeks in a
row. A record!
Okay, so this weekend,
as I mentioned in my last post, I’ve calculated the displacement of my vessel
and I’m pleasantly surprised.
The displacement of the
vessel is the amount determined as the amount of water it will displace, or
move, when sat in the water with a certain load.
If you think of putting
a bowl in a full tank of water. The bowl will sit on the surface of the water, floating,
after it has dropped so far down. At the point when its vertical movement has
stopped, the force it is exerted on the water is equal to the force the water
is exerting upon it. The water it has displaced from the tank will equal the
amount of volume of the bowl that sits below the water line. Therefore, the
volume of the vessel below the water line multiplied by the density of seawater
equals the weight of the boat plus its load. I believe this is known as Archimedes’
principle.
So what I have done, is
using a very rough version of Simpson’s/Trapezoidal rule is to make a
calculation of the volume of my vessel. I am not very accurate as I do not have formulae for the curvature on the hull, I have taken the difference between
the area of 2 bulkheads, divided it into steps and worked out the volume of the
vessel over 10mm intervals.
So, for the entire
volume of the vessel, I worked out the volume of the sections of the vessel like
this (section A-B is only 275mm long, hence no last interval):
Volume
|
Bulkhead
x to y
|
Step
|
1
|
2
|
3
|
---
|
27
|
28
|
29
|
5741781
|
A-B
|
0
|
1518.99
|
3037.979
|
---
|
39493.73
|
41012.72
|
||
16922035
|
B-C
|
44050.7
|
45072.21
|
46093.72
|
---
|
70609.97
|
71631.48
|
72652.99
|
|
24852949
|
C-D
|
73674.5
|
74533.45
|
75392.4
|
---
|
96007.24
|
96866.2
|
97725.15
|
|
28050694
|
D-E
|
94992.8
|
95116.64
|
95240.48
|
---
|
98212.59
|
98336.42
|
98460.26
|
|
23191072
|
E-F
|
65947.2
|
66948.77
|
67950.34
|
---
|
91988.08
|
92989.66
|
93991.23
|
|
13637687
|
F-G
|
29367.19
|
30628.57
|
31889.95
|
---
|
62163.06
|
63424.44
|
64685.82
|
For the entire volume
of the vessel:
Total Volume
|
1.12E+08
|
mm^3
|
Total Volume
|
0.112396
|
m^3
|
Density Seawater
|
1020
|
kg/m^3
|
Density Fresh water
|
1000
|
kg/m^4
|
Displacement in Saltwater
|
114.6441
|
kg
|
Displacement in Fresh Water
|
112.3962
|
kg
|
So, if we ignore the
weight of the vessel, that volume displacement should take my entire weight and
I won’t sink it? Hardcore!
So, I’ll look at a more
sensible displacement value now. I’ll calculate the displacement of the vessel
with the waterline 120mm from the deck:
Total Volume
|
44243653
|
mm^3
|
Total Volume
|
0.044244
|
m^3
|
Density Seawater
|
1020
|
kg/m^3
|
Density Fresh water
|
1000
|
kg/m^4
|
Displacement in Saltwater
|
45.12853
|
kg
|
Displacement in Fresh Water
|
44.24365
|
kg
|
This is pretty good. If
I can keep the entire weight of the vessel with all ancillaries onboard below
45kg, it’ll have 120mm between the deck and the waterline. Although this would
be brilliant if it comes out like this, I expect it to sit lower in the water than
that.
I’ll calculate the
weights of the vessel components and keep a running total as accurately as I
can during the build.
This has been a good
weekend of work! It proves that the design will work, I have a maximum weight
figure to work with and the vessel shouldn’t sink due to overloading. Shouldn’t,
not won’t. :)
Next Steps
- Finalise the carbon fibre mast size to use and bring into model.
- Keel bulb size and shape.
- Keel thickness review.
Until next weekend! Enjoy your
week!
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